Question 12 marksMake ttt the subject of the formula M=5t−8M = 5t - 8M=5t−8 Mark schemeMarks you got for part -, out of 2/ 2
Question 23 marks(a)Make xxx the subject of the formula y=x3y = \frac{x}{3}y=3x Mark schemeMarks you got for part a, out of 1/ 1(b)Make xxx the subject of the formula y=x3+5y = \frac{x}{3} + 5y=3x+5 Mark schemeMarks you got for part b, out of 2/ 2
Question 03 marksMake mmm the subject of the formula W=5m−23W = \frac{5m - 2}{3}W=35m−2 Mark schemeMarks you got for part -, out of 3/ 3
Question 03 marksThe perimeter, PPP cm, of this rectangle is given by the formula P=2(a+b)P = 2(a + b)P=2(a+b) b cma cm (a)Make bbb the subject of the formula P=2(a+b)P = 2(a + b)P=2(a+b) Mark schemeMarks you got for part a, out of 2/ 2(b)The perimeter of the rectangle is 262626 cm and a=4a = 4a=4. Use your answer to part (a) to work out the value of bbb. Mark schemeMarks you got for part b, out of 1/ 1
Question 04 markss=v28s = \frac{v^2}{8}s=8v2 (a)Make vvv the subject of the formula. Mark schemeMarks you got for part a, out of 2/ 2(b)vvv is a positive number. Use your answer to part (a) to complete the table. sss 222 888 vvv Mark schemeMarks you got for part b, out of 2/ 2
Question 04 marksS=h24−1S = \frac{h^2}{4} - 1S=4h2−1 (a)Make hhh the subject of the formula. hhh is a positive number. Mark schemeMarks you got for part a, out of 3/ 3(b)Use your answer to part (a) to work out the value of hhh when S=8S = 8S=8. Mark schemeMarks you got for part b, out of 1/ 1