Upper & Lower Bounds Flashcards

All 6 cards in this deck

How do you write the error interval for a value that has been rounded?

e.g. a length is 9090 m correct to the nearest metre

Go half the rounding unit either side: 89.5 m≤length<90.5 m89.5 \text{ m} \le \text{length} < 90.5 \text{ m}.

How do you write the error interval for a value that has been truncated?

e.g. NN truncated to 1 digit gives 77

From the truncated value up to the next value: 7≤N<87 \le N < 8.

To find the lower bound of a−ba-b, which bounds of aa and bb do you use?

LB(a)−UB(b)\text{LB}(a)-\text{UB}(b) — smallest aa take away largest bb.

Which bounds do you use to test whether an average speed could have been greater than a stated value, when the distance and time are both rounded?

The upper bound of the speed: UB(distance)÷LB(time)\text{UB(distance)} \div \text{LB(time)}, then compare it with the stated value.

What are the steps to give a calculated value to a suitable degree of accuracy by considering bounds?

e.g. d=c38d=\dfrac{c^3}{8} where c=10.9c=10.9 correct to 3 s.f.

  1. Use LB(c)=10.85\text{LB}(c)=10.85 and UB(c)=10.95\text{UB}(c)=10.95 in the formula: 159.66…159.66\ldots and 164.11…164.11\ldots
  2. Round both bounds until they agree: both give 160160
  3. State it with the reason: d=160d=160 since both bounds round to 160160

True or false? If a distance is measured to the nearest 5 km instead of the nearest km, the maximum possible average speed for a fixed time interval increases.

True. The bounds are wider (±2.5\pm 2.5 km instead of ±0.5\pm 0.5 km), so the upper bound of the distance is larger.