Factorising Out Terms Flashcards

All 5 cards in this deck

How do you find the common factor to take out of an algebraic expression?

e.g. 15x3+3x2y15x^3 + 3x^2y

Take the HCF of the number parts and the lowest power of each letter appearing in every term.

Here: 3x2(5x+y)3x^2(5x + y)

What are the steps to factorise by taking out a common factor?

e.g. 6x2+15x6x^2 + 15x

  1. HCF of the numbers: 33
  2. Lowest power of xx in every term: xx, so factor is 3x3x
  3. Divide each term by 3x3x: 3x(2x+5)3x(2x + 5)

True or false? x(9x+6)x(9x + 6) is a full factorisation of 9x2+6x9x^2 + 6x.

False. The bracket still has a common factor of 33; the full factorisation is 3x(3x+2)3x(3x + 2).

How do you factorise an expression with a bracketed common factor?

e.g. (x+y)2+3(x+y)(x + y)^2 + 3(x + y)

Treat the whole bracket as the common factor and take it out.

Here: (x+y)(x+y+3)(x + y)(x + y + 3)

True or false? When the common factor you take out is equal to one of the terms, that term becomes 11 inside the bracket.

True.

e.g. 6x+6=6(x+1)6x + 6 = 6(x + 1)