Roots of a Quadratic Equation

The second method is to find a same pair of numbers which add together to get the middle number in the quadratic equation which in the example is -3 and that same pair of numbers that multiply to get the 3rd number which is -4. This pair of numbers are the solution which is -4 and 1. Then equate both of these to 0 using x.

x-4=0 and x+1=0 ,, then the final values for x is 4 and -1. These are the roots of the quadratic equation.

The “roots” of a quadratic formula are essentially the X-Intercepts of a graph i.e. where does a graph cross the X-axis. Some quadratics will have two roots, some only one and some will have zero. A useful tool to know which category a quadratic falls into is to first use the discriminant which is b^2 - 4ac where a,b and c are the coefficients of ax^2 + box + c = 0 respectively. If the discriminant is positive there are two roots, if it is equal to zero then there is one root and if it is less than zero there are no real roots.

Once you know this you can either solve by factorising your quadratic which would involve taking out a common factor, or a difference of two squares or by solving a trinomial or any combination of these. Alternatively the quadratic formula could be used which can obtain the roots of any quadratic and it is given by x = [-b +- SQRT(b^2 - 4ac) ] / 2a or an online calculator could also be used!

To find how many roots of a quadratic formula there are use the part of the quadratic formula known as the derivative. This is root b^2 -4ac. If the answer to that is less than 0 then there is no real roots, if the answer is exactly 0, there is 1 real root. If the answer is more than 0 then there are 2 real roots.

I agree with Muhammed above. The easiest way is to use the formula. But you may be asked to factorize it too, if it can be factorized. Or by graph-the roots or solutions are where the curve crosses the y-axis.

you can solve it be discriminant method

The roots of a quadratic equation ax2 + bx + c = 0 can be found using the quadratic formula that says x = (-b ± √ (b2 - 4ac)) /2a.