Question 1
2 marksA student dissolves mol of potassium bromide in water.
The volume of the solution made is .
Calculate the concentration of the potassium bromide solution in .
[2 marks]
Concentration = ......................................
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A student dissolves 0.0600 mol of potassium bromide in water.
The volume of the solution made is 400 cm3.
Calculate the concentration of the potassium bromide solution in mol/dm3.
[2 marks]
Concentration = ...................................... mol/dm3
A technician is preparing a solution of sodium carbonate (Na2CO3) for a class practical.
The technician needs 500 cm3 of sodium carbonate solution with a concentration of 0.125 mol/dm3.
Calculate the mass of sodium carbonate (Na2CO3) the technician should dissolve.
Relative atomic masses (Ar): C = 12 O = 16 Na = 23
[3 marks]
Mass = ...................................... g
A sample of sea water contains dissolved sodium chloride (NaCl) at a concentration of 0.470 mol/dm3.
Calculate the mass of sodium chloride dissolved in 2.50 dm3 of this sea water.
Relative formula mass (Mr): NaCl = 58.5
Give your answer to 3 significant figures.
[3 marks]
Mass = ...................................... g
A student has 50.0 cm3 of copper(II) sulfate solution of concentration 0.400 mol/dm3.
The student pours all of this solution into a measuring cylinder and adds water until the total volume of the solution is 250 cm3.
Calculate the concentration, in mol/dm3, of the diluted copper(II) sulfate solution.
[3 marks]
Concentration = ...................................... mol/dm3
A student titrated calcium hydroxide solution with dilute nitric acid.
The equation for the reaction is:
2HNO3+Ca(OH)2→Ca(NO3)2+2H2O
The table shows the student's results.
| Solution | Volume in cm3 | Concentration in mol/dm3 |
|---|---|---|
| calcium hydroxide | 25.0 | 0.0500 |
| nitric acid | 22.4 | not known |
Calculate the concentration of the nitric acid in mol/dm3.
Give your answer to 3 significant figures.
[4 marks]
Concentration = ...................................... mol/dm3
A student titrated 25.0 cm3 of 0.0500 mol/dm3 sodium carbonate solution with dilute hydrochloric acid of unknown concentration.
The equation for the reaction is:
Na2CO3+2HCl→2NaCl+H2O+CO2
21.30 cm3 of the hydrochloric acid was needed to react completely with the 25.0 cm3 of sodium carbonate solution.
Calculate the concentration of the hydrochloric acid in g/dm3.
Relative formula mass (Mr): HCl = 36.5
[4 marks]
Concentration = ...................................... g/dm3
A bottle of sodium hydroxide solution is labelled:
sodium hydroxide solution, 8.00 g/dm3
25.0 cm3 of this sodium hydroxide solution was neutralised by exactly 20.0 cm3 of dilute sulfuric acid.
The equation for the reaction is:
H2SO4+2NaOH→Na2SO4+2H2O
Calculate the concentration of the sulfuric acid in mol/dm3.
Relative formula mass (Mr): NaOH = 40
[4 marks]
Concentration = ...................................... mol/dm3