Question 13 marksWrite 3x+24−x−56\frac{3x + 2}{4} - \frac{x - 5}{6}43x+2−6x−5 as a single fraction. Give your answer in its simplest form. Mark schemeMarks you got for part -, out of 3/ 3
Question 23 marksSimplify fully x2−7x+12x2−9\dfrac{x^{2} - 7x + 12}{x^{2} - 9}x2−9x2−7x+12 Mark schemeMarks you got for part -, out of 3/ 3
Question 03 marksWrite 2x−3+4x−12x - 3 + \dfrac{4}{x - 1}2x−3+x−14 as a single fraction. Give your answer in its simplest form. Mark schemeMarks you got for part -, out of 3/ 3
Question 03 marksWrite 5x2x2+x−6+3x+2\dfrac{5x}{2x^{2} + x - 6} + \dfrac{3}{x + 2}2x2+x−65x+x+23 as a single fraction. Give your answer in its simplest form. Mark schemeMarks you got for part -, out of 3/ 3
Question 04 marksSimplify fully 4p2−253p×12p10−4p\dfrac{4p^{2} - 25}{3p} \times \dfrac{12p}{10 - 4p}3p4p2−25×10−4p12p Mark schemeMarks you got for part -, out of 4/ 4
Question 04 marksSimplify fully x2−163x+6÷4x−16x2−4\dfrac{x^{2} - 16}{3x + 6} \div \dfrac{4x - 16}{x^{2} - 4}3x+6x2−16÷x2−44x−16 Mark schemeMarks you got for part -, out of 4/ 4
Question 05 marksYou are given the expression 4x−4−28x2−x−12\dfrac{4}{x - 4} - \dfrac{28}{x^{2} - x - 12}x−44−x2−x−1228 (a)Show that the expression simplifies to kx+3\dfrac{k}{x + 3}x+3k, where kkk is an integer. State the value of kkk. Mark schemeMarks you got for part a, out of 3/ 3(b)Hence solve 4x−4−28x2−x−12=12\dfrac{4}{x - 4} - \dfrac{28}{x^{2} - x - 12} = \dfrac{1}{2}x−44−x2−x−1228=21 Mark schemeMarks you got for part b, out of 2/ 2
Question 04 marksSolve 2x+1x+6=x+5x−2\dfrac{2x + 1}{x + 6} = \dfrac{x + 5}{x - 2}x+62x+1=x−2x+5 You must show your working. Mark schemeMarks you got for part -, out of 4/ 4
Question 04 marksg(θ)=2sin2θ−sinθcosθ6sinθcosθ−3cos2θg(\theta) = \dfrac{2\sin^{2}\theta - \sin\theta\cos\theta}{6\sin\theta\cos\theta - 3\cos^{2}\theta}g(θ)=6sinθcosθ−3cos2θ2sin2θ−sinθcosθ (a)Show that g(θ)=tanθ3g(\theta) = \dfrac{\tan\theta}{3}g(θ)=3tanθ Mark schemeMarks you got for part a, out of 2/ 2(b)Hence solve g(θ)=−13g(\theta) = -\dfrac{1}{3}g(θ)=−31 for 90°<θ<180°90° < \theta < 180°90°<θ<180° You must show your working. Mark schemeMarks you got for part b, out of 2/ 2