Question 13 marksf(x)=x3+4x2−7x−10f(x) = x^3 + 4x^2 - 7x - 10f(x)=x3+4x2−7x−10 (a)Work out f(1)f(1)f(1). Mark schemeMarks you got for part a, out of 1/ 1(b)Show that (x−2)(x - 2)(x−2) is a factor of f(x)f(x)f(x). Mark schemeMarks you got for part b, out of 2/ 2
Question 23 marks(a)Solve (3x+2)(x−4)(x+1)=0(3x + 2)(x - 4)(x + 1) = 0(3x+2)(x−4)(x+1)=0 Mark schemeMarks you got for part a, out of 2/ 2(b)g(x)g(x)g(x) is a polynomial and g(−5)=0g(-5) = 0g(−5)=0 Write down a linear factor of g(x)g(x)g(x). Mark schemeMarks you got for part b, out of 1/ 1
Question 04 marksFully factorise 2x3+3x2−11x−62x^3 + 3x^2 - 11x - 62x3+3x2−11x−6 Mark schemeMarks you got for part -, out of 4/ 4
Question 03 marks(2x+5)(2x + 5)(2x+5) is a factor of 2x3−x2−23x−202x^3 - x^2 - 23x - 202x3−x2−23x−20 Work out the other two linear factors. Mark schemeMarks you got for part -, out of 3/ 3
Question 04 marksSolve 4x3+12x2=7x4x^3 + 12x^2 = 7x4x3+12x2=7x Mark schemeMarks you got for part -, out of 4/ 4
Question 04 marksf(x)=2x5−x4+4x3−2x2−6x+3f(x) = 2x^5 - x^4 + 4x^3 - 2x^2 - 6x + 3f(x)=2x5−x4+4x3−2x2−6x+3 (a)Show that (2x−1)(2x - 1)(2x−1) is a factor of f(x)f(x)f(x). Mark schemeMarks you got for part a, out of 2/ 2(b)Is (x−3)(x - 3)(x−3) a factor of f(x)f(x)f(x)? You must show your working. Mark schemeMarks you got for part b, out of 2/ 2
Question 06 marks(3x+2)(3x + 2)(3x+2) is a factor of 6x3+ax2−7x−66x^3 + ax^2 - 7x - 66x3+ax2−7x−6 (a)Work out the value of aaa. Mark schemeMarks you got for part a, out of 3/ 3(b)Hence fully factorise 6x3+ax2−7x−66x^3 + ax^2 - 7x - 66x3+ax2−7x−6 using your value of aaa. Mark schemeMarks you got for part b, out of 3/ 3
Question 07 marksThe diagram shows a rectangular sheet of card measuring 20 cm by 12 cm. A square of side xxx cm is cut from each corner. The four flaps are then folded up to make an open box of volume VVV cm3^33. 20 cm12 cmx cmx cm (a)Show that V=4x3−64x2+240xV = 4x^3 - 64x^2 + 240xV=4x3−64x2+240x Mark schemeMarks you got for part a, out of 2/ 2(b)The volume of the box is 256256256 cm3^33 Show that x3−16x2+60x−64=0x^3 - 16x^2 + 60x - 64 = 0x3−16x2+60x−64=0 Mark schemeMarks you got for part b, out of 1/ 1(c)Work out the possible values of xxx. Give your answers as exact values and give a reason for rejecting any value you do not use. Mark schemeMarks you got for part c, out of 4/ 4
Question 07 marksf(x)=x3+px2+qx+24f(x) = x^3 + px^2 + qx + 24f(x)=x3+px2+qx+24 where ppp and qqq are constants. (x−2)(x - 2)(x−2) and (x+3)(x + 3)(x+3) are both factors of f(x)f(x)f(x). (a)Show that 2p+q=−162p + q = -162p+q=−16 Mark schemeMarks you got for part a, out of 2/ 2(b)Work out the value of ppp and the value of qqq. Mark schemeMarks you got for part b, out of 3/ 3(c)Hence solve f(x)=0f(x) = 0f(x)=0 Mark schemeMarks you got for part c, out of 2/ 2