Quadratic Simultaneous Equations Flashcards

All 6 cards in this deck

What are the steps to solve a linear and a quadratic equation simultaneously?

e.g. y=x2+3y = x^2 + 3 and y=4xy = 4x

  1. Substitute the linear equation into the quadratic: x2+3=4xx^2 + 3 = 4x.
  2. Rearrange to =0= 0 and solve: x2−4x+3=0x^2 - 4x + 3 = 0, so x=1x = 1 or x=3x = 3.
  3. Substitute each xx into the linear equation: x=1,y=4x = 1, y = 4 and x=3,y=12x = 3, y = 12.

For a linear/quadratic pair of simultaneous equations, which equation do you rearrange and which do you substitute into?

Rearrange the linear equation to make one variable the subject, then substitute it into the quadratic equation.

What are the steps to solve a circle equation and a straight line simultaneously?

e.g. x2+y2=25x^2 + y^2 = 25 and y=x+1y = x + 1

  1. Substitute the line into the circle: x2+(x+1)2=25x^2 + (x+1)^2 = 25.
  2. Expand and form a quadratic =0= 0, then solve: x2+x−12=0x^2 + x - 12 = 0, so x=3x = 3 or x=−4x = -4.
  3. Substitute each xx into the line: x=3,y=4x = 3, y = 4 and x=−4,y=−3x = -4, y = -3.

True or false? A straight line and a circle always meet at two points.

False. The line may be a tangent (one point) or miss the circle completely (no solutions).

When solving a line and a curve simultaneously, what does it mean if the resulting quadratic has a repeated root?

The line and curve meet at exactly one point, so the line is a tangent to the curve.

What are the steps to estimate the solutions of a circle equation and a linear equation using a given graph of the circle?

e.g. the graph of x2+y2=25x^2 + y^2 = 25 is drawn; solve it with y=x+1y = x + 1

  1. Draw the straight line on the same axes: line through (0,1)(0, 1) with gradient 11.
  2. Mark every point where the line crosses the circle: (3,4)(3, 4) and (−4,−3)(-4, -3).
  3. Read off each pair of coordinates as estimates: x=3,y=4x = 3, y = 4 and x=−4,y=−3x = -4, y = -3.