Volume & Surface Area Flashcards

All 19 cards in this deck

What is the formula for the volume of a prism?

e.g. a prism with cross-sectional area 12 cm212\text{ cm}^2 and length 55 cm

Volume = area of cross-section ×\times length

12×5=60 cm312 \times 5 = 60\text{ cm}^3

What is the formula for the volume of a cylinder of radius rr and height hh?

V=πr2hV = \pi r^2 h

What is the formula for the volume of a sphere of radius rr?

V=43πr3V = \frac{4}{3}\pi r^3

What is the formula for the volume of a cone of base radius rr and height hh?

V=13πr2hV = \frac{1}{3}\pi r^2 h, where hh is the perpendicular (vertical) height, not the slant height.

What is the formula for the volume of a pyramid?

V=13×V = \frac{1}{3} \times base area ×\times perpendicular height

How many cm3^3 are there in 1 litre?

1000 cm31000\text{ cm}^3, since 1 cm3=1 ml1\text{ cm}^3 = 1\text{ ml}.

What are the steps to find a missing height when the volume of a prism is given?

e.g. volume 60 cm360\text{ cm}^3, length 55 cm, triangular cross-section of base 44 cm

  1. Volume ÷\div length = cross-section area: 60÷5=12 cm260 \div 5 = 12\text{ cm}^2
  2. Put this into the area formula: 12×4×h=12\frac{1}{2}\times 4 \times h = 12
  3. Solve for hh: h=6h = 6 cm

What are the steps to find how long a container takes to fill at a given rate?

e.g. a tank of volume 6000 cm36000\text{ cm}^3 filled at 250 cm3250\text{ cm}^3 per second

  1. Work out the volume of the container: 6000 cm36000\text{ cm}^3
  2. Check the volume and the rate use the same units.
  3. Time = volume ÷\div rate: 6000÷250=246000 \div 250 = 24 seconds

What is the formula linking mass, density and volume of a solid?

mass = density ×\times volume, so density = mass ÷\div volume.

True or false? When a solid is melted down and recast into a different shape, its volume stays the same.

True. So you can equate the two volumes to find a missing length.

How do you find the total surface area of a prism?

e.g. a cuboid 77 cm by 66 cm by 55 cm

Add the areas of all its faces.

2(7×6+7×5+6×5)=214 cm22(7\times6 + 7\times5 + 6\times5) = 214\text{ cm}^2

What is the formula for the total surface area of a closed cylinder of radius rr and height hh?

2πr2+2πrh2\pi r^2 + 2\pi r h

The curved surface area alone is 2πrh2\pi r h.

What is the formula for the surface area of a sphere of radius rr?

4πr24\pi r^2

What is the formula for the total surface area of a solid cone?

πrl+πr2\pi r l + \pi r^2, where ll is the slant height.

True or false? The total surface area of a solid hemisphere of radius rr is 2πr22\pi r^2.

False. 2πr22\pi r^2 is only the curved part; the total is 2πr2+πr2=3πr22\pi r^2 + \pi r^2 = 3\pi r^2.

What are the steps to find the surface area of a composite solid?

e.g. a cylinder of radius rr, height hh, with a hemisphere of radius rr on top

  1. List the exposed surfaces of each part: curved cylinder, base circle, curved hemisphere.
  2. Leave out any joined or hidden faces: the top circle of the cylinder.
  3. Add the areas: 2πrh+πr2+2πr22\pi r h + \pi r^2 + 2\pi r^2

True or false? 1 m3=100 cm31\text{ m}^3 = 100\text{ cm}^3.

False. 1 m3=1 000 000 cm31\text{ m}^3 = 1\,000\,000\text{ cm}^3, since you multiply by 100100 for each of the three dimensions.

What are the steps to find the volume of a frustum of a cone?
e.g. a cone of radius 66 cm and height 1010 cm with the top cone of radius 33 cm and height 55 cm removed

  1. Volume of the full cone: 13π×62×10=120π\frac13\pi\times6^2\times10=120\pi
  2. Volume of the small cone removed: 13π×32×5=15π\frac13\pi\times3^2\times5=15\pi
  3. Subtract: 120π−15π=105π cm3120\pi-15\pi=105\pi\text{ cm}^3

True or false? The volume of a composite solid is always found by adding the volumes of the standard solids it can be split into.

False. If part of a solid has been removed (e.g. a drilled hole or the top of a cone), that volume is subtracted instead.