Combined Probabilities Flashcards

All 6 cards in this deck

What is the multiplication rule for two independent events?

e.g. P(Owen scores)=0.4P(\text{Owen scores})=0.4, P(Wasim scores)=0.25P(\text{Wasim scores})=0.25

P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B)

e.g. P(both score)=0.4×0.25=0.1P(\text{both score}) = 0.4 \times 0.25 = 0.1

What is the addition rule for mutually exclusive events?

e.g. P(win)=0.3P(\text{win})=0.3, P(draw)=0.1P(\text{draw})=0.1 in one game

P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B)

e.g. P(win or draw)=0.3+0.1=0.4P(\text{win or draw}) = 0.3 + 0.1 = 0.4

True or false? If P(Owen scores)=0.4P(\text{Owen scores}) = 0.4 and P(Wasim scores)=0.25P(\text{Wasim scores}) = 0.25, then the probability that both score is 0.4+0.250.4 + 0.25.

False. For 'both', independent probabilities should be multiplied: 0.4×0.250.4 \times 0.25.

True or false? P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B) for any two events AA and BB.

False. Adding only works for mutually exclusive events; otherwise an outcome could be in both categories and gets counted twice.

How do you find the probability of 'at least one' of several events happening?

e.g. two tests, P(fails both)=0.0351P(\text{fails both}) = 0.0351

1−P(none of them happen)1 - P(\text{none of them happen})

e.g. P(passes at least one)=1−0.0351=0.9649P(\text{passes at least one}) = 1 - 0.0351 = 0.9649

What are the steps to find the probability that exactly one of two independent events happens?

e.g. P(A)=0.3P(A)=0.3, P(B)=0.5P(B)=0.5

  1. P(A and not B)=0.3×0.5=0.15P(A \text{ and not } B) = 0.3 \times 0.5 = 0.15
  2. P(not A and B)=0.7×0.5=0.35P(\text{not } A \text{ and } B) = 0.7 \times 0.5 = 0.35
  3. Add the two: 0.15+0.35=0.50.15 + 0.35 = 0.5