Interpreting Cumulative Frequency Diagrams Flashcards

All 8 cards in this deck

How do you estimate the median from a cumulative frequency graph?
e.g. a graph for 6060 students

Read across from cumulative frequency n2=30\frac{n}{2}=30 to the curve, then down to the horizontal axis.

At which cumulative frequencies do you read off the lower and upper quartiles?
e.g. a graph for 6060 students

Lower quartile at n4=15\frac{n}{4}=15 and upper quartile at 3n4=45\frac{3n}{4}=45; read across to the curve then down.

How do you estimate the number of values greater than a given value from a cumulative frequency graph?
e.g. of 6060 students, how many are taller than 160160 cm

Read the cumulative frequency at that value and subtract it from the total: if the reading at 160160 is 4848, the answer is 60−48=1260-48=12.

How do you estimate the number of values between two given values from a cumulative frequency graph?
e.g. between 4040 g and 6060 g

Read the cumulative frequency at each value and subtract: if the readings are 2020 at 4040 g and 5050 at 6060 g, the answer is 50−20=3050-20=30.

How do you estimate the 90th percentile from a cumulative frequency graph?
e.g. a graph for 8080 items

Read across at 90%90\% of the total, 0.9×80=720.9\times80=72, then down to the horizontal axis.

How do you check a claim about the median using a cumulative frequency graph?

Read the median from the graph and compare it with the claimed value.
e.g. for 6060 potatoes, read across at 3030: the median is 5757 g, so the claim that it is 5050 g is wrong.

True or false? The median and quartiles found from a cumulative frequency graph are only estimates.

True. The original data is grouped, so exact values are unknown and readings from the curve are estimates.

How do you estimate what percentage of the data is below a given value on a cumulative frequency graph?

e.g. the percentage of 80 plants shorter than 90 cm

Read the cumulative frequency at that value, then divide by the total and multiply by 100.
e.g. reading 74 gives 7480×100=92.5%\frac{74}{80}\times100=92.5\%