Maths

>

GCSE

Positive and Negative Integers

Question

How do you find the least common multiple?

2 years ago

·

3 Replies

·

1595 views

D

Dayana Carroll


3 Answers

Andrew B Profile Picture
Andrew B Verified Sherpa Tutor ✓

University lecturer in maths and statistics

Once you have expressed both numbers as a product of prime factors, you then multiply together the highest power of numbers that appear in one or both products of prime factors

I'm available for 1:1 private online tuition!

Click here to view my profile and arrange a free introduction.
Richard A Profile Picture
Richard A Verified Sherpa Tutor ✓

Primary Teacher with 15 years teaching experience. 11+ tuition.

An excellent question! I like it! The lowest common multiple is found by listing the multiples of each number and circling and common multiples. The lowest one is the lowest common multiple!



I'm available for 1:1 private online tuition!

Click here to view my profile and arrange a free introduction.
Oscar P Profile Picture
Oscar P Verified Sherpa Tutor ✓

Energetic Oxford Engineering Student teaching Maths and Physics.

A longer explanation!


To define: a factor B of an integer A, exists if we can find some other integer C so B*C=A (effectively B is a factor of A if it multiples by some other integer to make A, for example 6 has factors 1,6,2 and 3). The highest common factor (HCF) of two numbers is therefore the largest factor that is a factor of both numbers.


On the other hand, a multiple A of some integer B, exists if we can find some integer C so that C*B=A (A is a multiplication of B). The lowest common multiple (LCM) of two numbers is therefore the lowest number that is multiple of both numbers.


We can find the highest common factor by using a factor tree (or called a prime tree), so we start with the number at the top of the tree and then draw two branches off below, using two factors of that number e.g 12 could go into 2 and 6. Then of those new numbers, we leave the prime numbers alone, which in this case is 2, then we split the other numbers further into factors, so 6 goes into 2 and 3, which are both now prime. So we have 2,2,3 as the prime factors of 12. We then get the other number we want to find the HCM and LCM of (compared with 12), for example we could choose 8. To find the HCF of 12 and 8, we also split 8 into a factor tree and get 2,2,2. Then the HCF uses the prime factors that exist in both numbers and multiplies them together: here both 12 and 8 have two 2s, so we know the HCF is 2*2=4. Then to find the LCM of 12 and 8, we use the remaining prime factors that haven't been used yet and multiply the HCF by these. So in this case we have 3 remaining from 12, and 2 remaining from 8, so the LCM is 4*3*2=24.

I'm available for 1:1 private online tuition!

Click here to view my profile and arrange a free introduction.

Think you can help?

More Maths GCSE Questions
Sherpa Badge

Need a GCSE Maths tutor?

Get started with a free online introductions with an experienced and qualified online tutor on Sherpa.

Find a GCSE Maths Tutor