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What is th...
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Rusty Botsford
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(Free Trial Lesson) MSc. Mathematics Distinction
Let E be the set of all possible results of an experiment. We are also denote the results that are asked for/investigated as the set A.
Then the probability of the event A, which is having one of the results in the set A, is equal to (Number of elements in A) divided by (Number of all elements).
For example, say that we throw a die with a friend one-by-one. Our friend throws the die and gets a 1. If we get a 2, 3, 4, 5, or 6, we are winning this round. So, the results that we ask for is A={2, 3, 4, 5, 6} and all possible results are E={1,2,3,4,5,6}.
Hence, the probability that we win this round is (Number of elements in A) = 5, divided by (Number of all elements) = 6, which is 5/6.
If our friend had scored a 2, we would win if we scored a 3, 4, 5 or 6. Then the probability that we win would be (Number of elements in A) = 4, divided by (Number of all elements) = 6, which is 4/6 = 2/3.
If our friend had scored a 3, we would win if we scored a 4, 5 or 6. Then the probability that we win would be (Number of elements in A) = 3, divided by (Number of all elements) = 6, which is 3/6.
If our friend had scored a 4, we would win if we scored a 5 or 6. Then the probability that we win would be (Number of elements in A) = 2, divided by (Number of all elements) = 6, which is 2/6 = 1/3.
If our friend had scored a 5, we would win only if we scored a 6. Then the probability that we win would be (Number of elements in A) = 1, divided by (Number of all elements) = 6, which is 1/6.
Our friend cannot score a 0 because 0 does not appear on the die. Also, if our friend scores a 6, then we cannot win that round, because there is no larger number on the die, which would have allowed us to win.
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Click here to view my profile and arrange a free introduction.Probability of a favourable event P(E) = (Number of favourable outcomes) ÷ (Number of Elements in Sample space).
Probability is the number of ways the outcome can happen over the total possible number of outcomes. For example, if you want to find the probability of receiving an order early from a particular delivery company, you would take the number of times they have delivered early, lets say 10, over the number of deliveries in total, lets say 100. Hence the probability would be 10/100, which is 1/10, which you could write out as 0.1.
Think of it as a magical recipe where you count the number of ways your desired outcome can happen and divide it by all the possible outcomes in the universe of your experiment.
It's like making a potion—mixing the right ingredients for a successful outcome!
The mathematical formula for an event E is given as:
Probability = (Number of a Favourable outcome) / (Total number of outcomes) P = n (E) / n (S) Where P is the probability, E is the event and S is the sample space.
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Probability of impossible event is zero. Probability of certain event is 1. And in general probability of an event = favourable cases for an event / total possible cases.
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Click here to view my profile and arrange a free introduction.number of objects in interest / total number of objects
P(E) = n(E)/n(s)
Where n(E) is number of points
n(s) is the number of sample
No. Of favourable conditions divided by total no. Of outcomes
The formula to find probability is
Probability = (Number of a Favourable outcome) / (Total number of outcomes)
Hi Rusty,
Probability = Number of favourable Outcomes / Total Number of Outcomes
p (A) = f / N
You need to start by finding the probability of a single outcome. Then find the total number of outcomes that can occur. Finally divide the number of events by the number of possible outcomes.
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Probability of an event = (number of favourable outcomes) / (total number of outcomes)
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Click here to view my profile and arrange a free introduction.Probability of event 'A' is equal to (Number of Event A occurred) divided by (Total Number of Events occurred in Sample Space):
P(A) = n(A)/n(S); where 'A' is Event 'A' Occurred and 'S' is Total Number of Events in Sample Space
Rule for addition- P(AuB)=P(A)+P(B)-P(AnB)
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