Linear Graphs Flashcards

All 16 cards in this deck

What is the gradient of a line with equation y=mx+cy = mx + c?

e.g. y=2x+3y = 2x + 3

mm, the coefficient of xx.

So y=2x+3y = 2x + 3 has gradient 22.

What are the coordinates of the point where the line y=mx+cy = mx + c crosses the yy-axis?

e.g. y=−4x+3y = -4x + 3

(0,c)(0, c).

So y=−4x+3y = -4x + 3 crosses at (0,3)(0, 3).

What are the steps to find the gradient of a line whose equation is not in the form y=mx+cy = mx + c?

e.g. 3y−9x=63y - 9x = 6

  1. Get the yy term alone: 3y=9x+63y = 9x + 6
  2. Divide every term by the number in front of yy: y=3x+2y = 3x + 2
  3. The gradient is the coefficient of xx: 33

What are the steps to find the equation of the line through two given points?

e.g. through (0,3)(0, 3) and (2,−1)(2, -1)

  1. Gradient m=change in ychange in x=−1−32−0=−2m = \frac{\text{change in } y}{\text{change in } x} = \frac{-1-3}{2-0} = -2
  2. Find cc from a point on the line: the line crosses the yy-axis at (0,3)(0,3), so c=3c = 3
  3. Write y=mx+cy = mx + c: y=−2x+3y = -2x + 3

What are the steps to find the equation of a line through one point with a given gradient?

e.g. gradient 44 through (2,9)(2, 9)

  1. Write y=mx+cy = mx + c with the gradient: y=4x+cy = 4x + c
  2. Substitute the point's coordinates: 9=4×2+c9 = 4 \times 2 + c
  3. Solve for cc and write the equation: c=1c = 1, so y=4x+1y = 4x + 1

How do you check algebraically whether a point lies on a given straight line?

e.g. does (2,9)(2, 9) lie on y=4x+1y = 4x + 1?

Substitute the xx-coordinate into the equation and see if you get the yy-coordinate.

4×2+1=94 \times 2 + 1 = 9, so yes, (2,9)(2, 9) lies on the line.

What are the steps to complete a table of values for a linear equation?

e.g. y=4x−6y = 4x - 6 for x=−1,0,1x = -1, 0, 1

  1. Substitute the first xx value into the equation: 4×(−1)−6=−104 \times (-1) - 6 = -10
  2. Repeat for each xx value: x=0x = 0 gives −6-6, x=1x = 1 gives −2-2
  3. Write each yy value under its xx value

What are the steps to draw the graph of y=mx+cy = mx + c over a given range of xx?

e.g. y=12x−1y = \frac{1}{2}x - 1 for xx from −2-2 to 33

  1. Complete a table of values: y=−2,−1.5,−1,−0.5,0,0.5y = -2, -1.5, -1, -0.5, 0, 0.5
  2. Plot the points, e.g. (−2,−2)(-2, -2) and (3,0.5)(3, 0.5)
  3. Join them with a single ruled straight line from x=−2x = -2 to x=3x = 3

What does the graph of x=−2x = -2 look like?

A vertical line through (−2,0)(-2, 0), parallel to the yy-axis.

Every point on it has xx-coordinate −2-2.

What does the graph of y=−3y = -3 look like?

A horizontal line through (0,−3)(0, -3), parallel to the xx-axis.

Every point on it has yy-coordinate −3-3.

How do you find the gradient of a straight line drawn on a grid?

e.g. a line passing through (1,2)(1, 2) and (4,8)(4, 8)

Gradient =change in ychange in x= \frac{\text{change in } y}{\text{change in } x} between two points on the line.

8−24−1=2\frac{8-2}{4-1} = 2

How can you tell from their equations that two straight lines are parallel?

They have the same gradient (the same value of mm in y=mx+cy = mx + c) but different values of cc.

e.g. y=3x−2y = 3x - 2 and y=3x+5y = 3x + 5

What are the steps to show that two lines are parallel when one is not in the form y=mx+cy = mx + c?

e.g. y=3x−2y = 3x - 2 and 3y−9x+5=03y - 9x + 5 = 0

  1. Rearrange into y=mx+cy = mx + c: 3y=9x−53y = 9x - 5, so y=3x−53y = 3x - \frac{5}{3}
  2. Compare the coefficients of xx: both are 33
  3. State the conclusion: both lines have gradient 33, so they are parallel

Write down the equation of a straight line parallel to y=5xy = 5x.

Any line y=5x+cy = 5x + c with c≠0c \neq 0.

e.g. y=5x+2y = 5x + 2

True or false? The lines y=2x+1y = 2x + 1 and y=3x+1y = 3x + 1 are parallel.

False.

Their gradients differ (22 and 33); they both pass through (0,1)(0, 1), so they cross there.

True or false? Two different parallel lines can have the same yy-intercept.

False.

Same gradient and same yy-intercept means they are the same line.