Expanding Triple Brackets Flashcards

All 5 cards in this deck

What are the steps to expand and simplify three binomials?

e.g. (x+1)(x+2)(x+3)(x+1)(x+2)(x+3)

  1. Multiply two of the brackets: (x+1)(x+2)=x2+3x+2(x+1)(x+2)=x^2+3x+2
  2. Multiply that quadratic by the remaining bracket, each term by each: x3+3x2+2x+3x2+9x+6x^3+3x^2+2x+3x^2+9x+6
  3. Collect like terms: x3+6x2+11x+6x^3+6x^2+11x+6

What form does the expansion of three linear brackets take?

A cubic, ax3+bx2+cx+dax^3+bx^2+cx+d.

How many terms do you get when multiplying a simplified 3-term quadratic by a binomial, before simplifying?

Six terms.

True or false? When expanding three brackets you must multiply the first two brackets first.

False. Any pair can be multiplied first; the final cubic is the same.

When three linear brackets are expanded to ax3+bx2+cx+dax^3+bx^2+cx+d, how can you check aa and dd quickly?

e.g. (2x+1)(x+3)(3x+7)(2x+1)(x+3)(3x+7)

aa is the product of the xx-coefficients and dd is the product of the constants.
a=2×1×3=6a=2\times1\times3=6, d=1×3×7=21d=1\times3\times7=21