Factorising Simple Quadratics Flashcards

All 5 cards in this deck

To factorise x2+bx+cx^2 + bx + c as (x+p)(x+q)(x + p)(x + q), what must pp and qq satisfy?

p+q=bp + q = b and pq=cpq = c.

e.g. for x2+5x+6x^2 + 5x + 6 the numbers add to 55 and multiply to 66.

What are the steps to factorise a quadratic of the form x2+bx+cx^2 + bx + c?

e.g. x2+5x+6x^2 + 5x + 6

  1. Find two numbers with product cc and sum bb: product 66, sum 55 → 22 and 33
  2. Put them in brackets with xx: (x+2)(x+3)(x + 2)(x + 3)

True or false? To factorise x2+5x+6x^2 + 5x + 6 the two numbers must add to 66 and multiply to 55.

False. It is the other way round: the sum must be 55 and the product must be 66.

In x2+bx+cx^2 + bx + c with cc negative, what are the signs of the two numbers in the brackets?

One positive and one negative.

e.g. x2+3x−10=(x+5)(x−2)x^2 + 3x - 10 = (x + 5)(x - 2)

In x2+bx+cx^2 + bx + c with cc positive and bb negative, what are the signs of the two numbers in the brackets?

Both negative.

e.g. x2−7x+12=(x−3)(x−4)x^2 - 7x + 12 = (x - 3)(x - 4)