Quadratic Sequences Flashcards

All 5 cards in this deck

What is the general form of the nnth term of a quadratic sequence?

an2+bn+can^2+bn+c, where a≠0a\neq0.

How do you get the coefficient of n2n^2 from the second difference of a quadratic sequence?

e.g. constant second difference 44

Halve the second difference: a=42=2a=\tfrac{4}{2}=2, so the nnth term contains 2n22n^2.

What are the steps to find the nnth term of a quadratic sequence?

e.g. 3,9,17,273, 9, 17, 27

  1. Second difference is 22, so halve it: the n2n^2 term is n2n^2
  2. Subtract 1,4,9,161, 4, 9, 16 from the terms: 2,5,8,112, 5, 8, 11, which has nnth term 3n−13n-1
  3. nnth term =n2+3n−1=n^2+3n-1

True or false? In a quadratic sequence the first differences are constant.

False. The second differences are constant; the first differences change by a fixed amount.

What are the steps to find unknown coefficients in an nnth term rule from given terms?

e.g. nnth term =an2+bn=an^2+bn, 2nd term =−2=-2, 4th term =12=12

  1. Substitute n=2n=2: 4a+2b=−24a+2b=-2
  2. Substitute n=4n=4: 16a+4b=1216a+4b=12
  3. Solve the two equations together: a=2a=2, b=−5b=-5