Calculating Pressure in a Liquid Flashcards

All 7 cards in this deck

What is the equation for the pressure due to a column of liquid?

P=h×ρ×gP = h \times \rho \times g — pressure = height (depth) of column ×\times density ×\times gravitational field strength.

State the units of each quantity in P=hρgP = h \rho g.

PP in Pa, hh in m, ρ\rho in kg/m3^3, gg in N/kg.

What are the steps to calculate the pressure due to a column of liquid?

e.g. water of density 10001000 kg/m3^3 at a depth of 33 m, g=10g = 10 N/kg

  1. Select P=hρgP = h\rho g
  2. Substitute: P=3×1000×10P = 3 \times 1000 \times 10
  3. Pressure =30 000= 30\,000 Pa

What are the steps to find the depth hh from a pressure due to a liquid?

e.g. P=20 000P = 20\,000 Pa in water, ρ=1000\rho = 1000 kg/m3^3, g=10g = 10 N/kg

  1. Write P=hρgP = h\rho g and substitute: 20 000=h×1000×1020\,000 = h \times 1000 \times 10
  2. Rearrange: h=20 0001000×10h = \dfrac{20\,000}{1000 \times 10}
  3. h=2h = 2 m

What are the steps to find the difference in pressure between two depths in a liquid?

e.g. between 22 m and 55 m deep in water (ρ=1000\rho = 1000 kg/m3^3, g=10g = 10 N/kg)

  1. Find the difference in depth: 5−2=35 - 2 = 3 m
  2. Use ΔP=Δh×ρ×g=3×1000×10\Delta P = \Delta h \times \rho \times g = 3 \times 1000 \times 10
  3. Difference in pressure =30 000= 30\,000 Pa

True or false? In P=hρgP = h\rho g, hh is the total height of the container.

False. hh is the depth of the point below the surface of the liquid.

Does P=hρgP = h\rho g give the total pressure at a depth in an open tank?

No — it gives only the pressure due to the liquid; add atmospheric pressure for the total.