Calculating Uniform Acceleration Flashcards

All 5 cards in this deck

What is the equation linking final velocity, initial velocity, acceleration and distance for uniform acceleration?

v2−u2=2×a×xv^2 - u^2 = 2 \times a \times x, where xx is the distance in metres.

When should you use v2−u2=2axv^2 - u^2 = 2ax instead of a=(v−u)÷ta = (v-u) \div t?

When the question involves distance and the time taken is not known.

True or false? In the equation v2−u2=2axv^2 - u^2 = 2ax, xx stands for the time taken.

False. xx is the distance travelled in metres.

What value of initial velocity uu do you use for an object that starts from rest?

u=0u = 0 m/s.

What are the steps to find the distance travelled using v2−u2=2axv^2 - u^2 = 2ax?

e.g. a cyclist accelerates from rest to 10 m/s at 2 m/s2^2

  1. Substitute: 102−02=2×2×x10^2 - 0^2 = 2 \times 2 \times x
  2. Rearrange: x=1004x = \dfrac{100}{4}
  3. Distance = 25 m