Factorising Quadratics Flashcards

All 6 cards in this deck

To factorise x2+bx+cx^2 + bx + c into (x+a)(x+d)(x + a)(x + d), what must the two numbers do?

Multiply to give cc and add to give bb.
e.g. x2+4x+3=(x+1)(x+3)x^2 + 4x + 3 = (x + 1)(x + 3)

What are the steps to factorise a quadratic of the form x2+bx+cx^2 + bx + c?

e.g. x2+10x+9x^2 + 10x + 9

  1. List pairs multiplying to cc: 1×91 \times 9, 3×33 \times 3
  2. Choose the pair adding to b=10b = 10: 11 and 99
  3. Write two brackets: (x+1)(x+9)(x + 1)(x + 9)

In x2+bx+cx^2 + bx + c, if cc is negative, what signs go in the two brackets?

One ++ and one −-.
e.g. x2+2x−8=(x+4)(x−2)x^2 + 2x - 8 = (x + 4)(x - 2)

In x2+bx+cx^2 + bx + c, if cc is positive and bb is negative, what signs go in the two brackets?

Both −-.
e.g. x2−7x+12=(x−3)(x−4)x^2 - 7x + 12 = (x - 3)(x - 4)

How is the factorised answer written when a quadratic is a perfect square?

e.g. x2+6x+9x^2 + 6x + 9

As a squared bracket: (x+3)2(x + 3)^2, or (x+3)(x+3)(x + 3)(x + 3) — both are accepted.

True or false? To factorise x2+bx+cx^2 + bx + c you need two numbers that add to cc and multiply to bb.

False.
It is the other way round: they multiply to cc and add to bb.