Algebraic Fractions Flashcards

All 7 cards in this deck

What are the steps to write an expression made of whole terms and fractions as a single fraction in simplest form?
e.g. 2+3x−12x2 + \frac{3}{x} - \frac{1}{2x}

  1. Choose a common denominator: 2x2x
  2. Rewrite every term over it: 4x2x+62x−12x\frac{4x}{2x} + \frac{6}{2x} - \frac{1}{2x}
  3. Combine the numerators into one fraction: 4x+52x\frac{4x+5}{2x}

What are the steps to simplify fully a fraction with a quadratic numerator and a quadratic denominator?
e.g. x2+4x+3x2−9\frac{x^2+4x+3}{x^2-9}

  1. Factorise the numerator into two brackets: (x+3)(x+1)(x+3)(x+1)
  2. Factorise the denominator into two brackets: (x+3)(x−3)(x+3)(x-3)
  3. Cancel the common bracket: x+1x−3\frac{x+1}{x-3}

What are the steps to divide one algebraic fraction by another and simplify fully?
e.g. 4a+2÷8a2−4\frac{4}{a+2} \div \frac{8}{a^2-4}

  1. Multiply by the reciprocal of the second fraction: 4a+2×a2−48\frac{4}{a+2} \times \frac{a^2-4}{8}
  2. Factorise and write as one fraction: 4(a+2)(a−2)8(a+2)\frac{4(a+2)(a-2)}{8(a+2)}
  3. Cancel common factors: a−22\frac{a-2}{2}

True or false? sin⁡x(3cos⁡x+sin⁡x)4cos⁡x(3cos⁡x+sin⁡x)\frac{\sin x(3\cos x + \sin x)}{4\cos x(3\cos x + \sin x)} simplifies to tan⁡x4\frac{\tan x}{4}.

True. The common bracket cancels to give sin⁡x4cos⁡x\frac{\sin x}{4\cos x}, and sin⁡xcos⁡x=tan⁡x\frac{\sin x}{\cos x} = \tan x.

What are the steps to subtract/add algebraic fractions where one denominator is quadratic and factorises?

e.g. 1x−2+3x2−4\frac{1}{x-2} + \frac{3}{x^2-4}

  1. Factorise the quadratic denominator: x2−4=(x−2)(x+2)x^2-4=(x-2)(x+2)
  2. Write both over the common denominator (x−2)(x+2)(x-2)(x+2): x+2(x−2)(x+2)+3(x−2)(x+2)\frac{x+2}{(x-2)(x+2)}+\frac{3}{(x-2)(x+2)}
  3. Combine the numerators and simplify: x+5(x−2)(x+2)\frac{x+5}{(x-2)(x+2)}

What are the steps to show an expression simplifies to a given form and to find the constant kk?

e.g. show 2x−1−2x+1=kx2−1\frac{2}{x-1}-\frac{2}{x+1}=\frac{k}{x^2-1}

  1. Write as a single fraction over the common denominator: 2(x+1)−2(x−1)(x−1)(x+1)\frac{2(x+1)-2(x-1)}{(x-1)(x+1)}
  2. Expand and simplify the numerator: 4x2−1\frac{4}{x^2-1}
  3. Compare with the given form: k=4k=4

What are the steps to solve an equation where one algebraic fraction equals another?

e.g. x+25=x−12\frac{x+2}{5}=\frac{x-1}{2}

  1. Cross-multiply: 2(x+2)=5(x−1)2(x+2)=5(x-1)
  2. Expand both brackets: 2x+4=5x−52x+4=5x-5
  3. Collect terms and solve: x=3x=3