Equation of a Circle Flashcards

All 13 cards in this deck

What is the equation of a circle with centre (0,0)(0,0) and radius rr?

e.g. radius 5

x2+y2=r2x^2 + y^2 = r^2

e.g. x2+y2=25x^2 + y^2 = 25

What is the equation of a circle with centre (a,b)(a,b) and radius rr?

e.g. centre (2,−3)(2,-3), radius 4

(x−a)2+(y−b)2=r2(x-a)^2 + (y-b)^2 = r^2

e.g. (x−2)2+(y+3)2=16(x-2)^2 + (y+3)^2 = 16

True or false? The circle (x+7)2+(y−4)2=36(x+7)^2 + (y-4)^2 = 36 has centre (7,−4)(7,-4) and radius 36.

False. The centre is (−7,4)(-7,4) and the radius is 6, because the right-hand side is r2r^2.

What are the steps to decide whether a point lies inside, on or outside a circle?

e.g. where does (1,2)(1,2) lie for x2+y2=25x^2 + y^2 = 25?

  1. Substitute the point into the left-hand side: 12+22=51^2 + 2^2 = 5
  2. Compare with r2r^2: 5<255 < 25
  3. Less than r2r^2 = inside, equal = on, greater = outside: inside

What are the steps to find the equation of a circle given the two endpoints of a diameter?

e.g. diameter from (1,2)(1,2) to (5,8)(5,8)

  1. Centre = midpoint of the diameter: (3,5)(3,5)
  2. r2r^2 = squared distance from centre to an endpoint: 22+32=132^2 + 3^2 = 13
  3. Write it in the standard form: (x−3)2+(y−5)2=13(x-3)^2 + (y-5)^2 = 13

What are the steps to find the coordinates where a line meets a circle?

e.g. x2+y2=25x^2 + y^2 = 25 and x=2y−5x = 2y - 5

  1. Substitute the line into the circle equation: (2y−5)2+y2=25(2y-5)^2 + y^2 = 25
  2. Expand and simplify, then solve: 5y2−20y=05y^2 - 20y = 0, so y=0y = 0 or y=4y = 4
  3. Put each value back into the line: (−5,0)(-5,0) and (3,4)(3,4)

How is the gradient of a tangent related to the gradient of the radius drawn to the point of contact?

e.g. radius of gradient 52\frac{5}{2}

It is the negative reciprocal, because the tangent and radius meet at 90°.

e.g. tangent gradient −25-\frac{2}{5}

What are the steps to find the equation of the tangent to a circle at a given point on it?

e.g. tangent to x2+y2=25x^2 + y^2 = 25 at (3,4)(3,4)

  1. Gradient of the radius from the centre to the point: 43\frac{4}{3}
  2. Tangent gradient = negative reciprocal: −34-\frac{3}{4}
  3. Use y−y1=m(x−x1)y - y_1 = m(x - x_1): y−4=−34(x−3)y - 4 = -\frac{3}{4}(x-3)

What do you know about the two tangents drawn from the same external point to a circle?

They are equal in length.

What is the size of the angle in a semi-circle?

90°. The angle subtended at any point of the circle by a diameter is a right angle.

What are the steps to find the length of a chord from the radius and the distance of the chord from the centre?

e.g. radius 5, chord 3 from the centre

  1. The perpendicular from the centre bisects the chord, giving a right-angled triangle with hypotenuse rr: sides 3, half-chord, 5
  2. Pythagoras for half the chord: 52−32=4\sqrt{5^2 - 3^2} = 4
  3. Double it: chord =8= 8

What are the steps to test whether a line is a tangent to a circle?

e.g. is y=5y = 5 a tangent to x2+y2=25x^2 + y^2 = 25?

  1. Substitute the line into the circle equation: x2+25=25x^2 + 25 = 25, i.e. x2=0x^2 = 0
  2. Find the discriminant b2−4acb^2 - 4ac of the quadratic: 00
  3. Zero = tangent, negative = misses, positive = cuts at two points: tangent

True or false? The perpendicular from the centre of a circle to a chord bisects the chord.

True. It meets the chord at its midpoint, so the radius, half-chord and this perpendicular form a right-angled triangle.