Binomial Expansion Flashcards

All 10 cards in this deck

In the expansion of (a+b)n(a+b)^n, what is the term containing brb^r?

e.g. the term in b2b^2 in (a+b)6(a+b)^6

(nr)an−rbr\binom{n}{r}a^{n-r}b^r

e.g. (62)a4b2=15a4b2\binom{6}{2}a^4b^2 = 15a^4b^2

What is (nr)\binom{n}{r} (also written nCr^nC_r) equal to as a formula?

(nr)=n!r!(n−r)!\binom{n}{r}=\dfrac{n!}{r!(n-r)!}

e.g. (52)=1202×6=10\binom{5}{2}=\dfrac{120}{2\times 6}=10

What are the steps to write the next row of Pascal's triangle?

e.g. the row after 1, 4, 6, 4, 11,\ 4,\ 6,\ 4,\ 1

  1. Start with 1: 11
  2. Add each adjacent pair: 1+4=51+4=5, 4+6=104+6=10, 6+4=106+4=10, 4+1=54+1=5
  3. End with 1: row is 1, 5, 10, 10, 5, 11,\ 5,\ 10,\ 10,\ 5,\ 1 (coefficients for power 5)

What are the steps to expand and simplify a cube of a bracket?

e.g. (5x+2)3(5x+2)^3

  1. Coefficients from Pascal's triangle: 1, 3, 3, 11,\ 3,\ 3,\ 1
  2. Terms: (5x)3+3(5x)2(2)+3(5x)(2)2+(2)3(5x)^3+3(5x)^2(2)+3(5x)(2)^2+(2)^3
  3. Simplify: 125x3+150x2+60x+8125x^3+150x^2+60x+8

What happens to the signs when you expand (a−bx)n(a-bx)^n?

e.g. (1−x)4(1-x)^4

The signs alternate +,−,+,−,…+,-,+,-,\dots because the whole (−bx)(-bx) is raised to each power.

e.g. 1−4x+6x2−4x3+x41-4x+6x^2-4x^3+x^4

True or false? In the expansion of (2+3x)4(2+3x)^4 the x2x^2 term is (42)×22×3x2\binom{4}{2}\times 2^2\times 3x^2.

False. The whole 3x3x must be squared: (42)×22×(3x)2=216x2\binom{4}{2}\times 2^2\times (3x)^2 = 216x^2.

What are the steps to find the coefficient of a given power of xx without expanding fully?

e.g. the coefficient of x2x^2 in (3+ax)5(3+ax)^5

  1. Choose rr to match the power: r=2r=2
  2. Write (nr)×(first term)n−r×(second term)r\binom{n}{r}\times(\text{first term})^{n-r}\times(\text{second term})^r: (52)×33×(ax)2\binom{5}{2}\times 3^3\times (ax)^2
  3. Evaluate: 10×27×a2=270a210\times 27\times a^2 = 270a^2

True or false? In the term 270a2x2270a^2x^2, the coefficient of x2x^2 is 270a2270a^2.

True. The coefficient is the whole factor multiplying x2x^2, without the x2x^2 itself.

What are the steps to find an unknown by comparing coefficients in two expansions?

e.g. the coefficient of x2x^2 in (2+3x)4(2+3x)^4 equals the coefficient of x2x^2 in (a+x)3(a+x)^3

  1. Coefficient from the first expansion: (42)×22×32=216\binom{4}{2}\times 2^2\times 3^2=216
  2. Coefficient from the second: (32)×a=3a\binom{3}{2}\times a=3a
  3. Equate and solve: 3a=2163a=216, so a=72a=72

What are the steps when one coefficient of an expansion is a multiple of another?

e.g. in (3+ax)5(3+ax)^5 the coefficient of x4x^4 is 88 times the coefficient of x2x^2

  1. Coefficient of x2x^2: (52)×33×a2=270a2\binom{5}{2}\times 3^3\times a^2=270a^2
  2. Coefficient of x4x^4: (54)×3×a4=15a4\binom{5}{4}\times 3\times a^4=15a^4
  3. Form and solve the equation: 15a4=8×270a215a^4=8\times 270a^2, so a2=144a^2=144 and a=±12a=\pm 12