Right-Angled Trigonometry Flashcards

All 7 cards in this deck

What is Pythagoras' theorem?

a2+b2=c2a^2 + b^2 = c^2, where cc is the hypotenuse (the side opposite the right angle).

Which Pythagorean triples should you recognise?

3, 4, 5; 5, 12, 13; 8, 15, 17; 7, 24, 25 — and any multiple of these.
e.g. 6, 8, 10 and 10, 24, 26

What are the steps to find a missing side in a right-angled triangle using trigonometry?

e.g. find the side opposite a 30° angle when the hypotenuse is 12 cm

  1. Label the sides O, A, H relative to the given angle: O = xx, H = 12.
  2. Choose the ratio (SOH CAH TOA): sin⁡30°=x12\sin 30° = \frac{x}{12}.
  3. Rearrange and solve: x=12sin⁡30°=6x = 12 \sin 30° = 6 cm.

What are the steps to find a missing angle in a right-angled triangle using trigonometry?

e.g. opposite = 5 cm, hypotenuse = 10 cm

  1. Label the sides: O = 5, H = 10.
  2. Choose the ratio: sin⁡θ=510\sin \theta = \frac{5}{10}.
  3. Use the inverse function: θ=sin⁡−1(0.5)=30°\theta = \sin^{-1}(0.5) = 30°.

What are the side ratios of a 30°, 60°, 90° triangle?

1:3:21 : \sqrt{3} : 2 — the side opposite 30° is 1, opposite 60° is 3\sqrt{3}, and the hypotenuse is 2.

What are the side ratios of a 45°, 45°, 90° triangle?

1:1:21 : 1 : \sqrt{2} — the two equal sides are opposite the 45° angles and the hypotenuse is 2\sqrt{2} times a shorter side.

What are the steps to find the length of a chord from the radius and the perpendicular distance of the chord from the centre?

e.g. radius 5 cm, chord 3 cm from the centre

  1. The perpendicular from the centre bisects the chord, giving a right-angled triangle with hypotenuse 5 and one side 3.
  2. Pythagoras for half the chord: 52−32=4\sqrt{5^2 - 3^2} = 4.
  3. Double it: chord =8= 8 cm.