Polynomials & Factor Theorem Flashcards

All 13 cards in this deck

State the factor theorem.

If f(a)=0f(a)=0, then (x−a)(x-a) is a factor of the polynomial f(x)f(x) (and if (x−a)(x-a) is a factor, then f(a)=0f(a)=0).

Which value of xx do you substitute to test whether 2x−32x-3 is a factor of a polynomial f(x)f(x)?

x=32x=\frac{3}{2} (solve 2x−3=02x-3=0). If f(32)=0f\left(\frac{3}{2}\right)=0, then 2x−32x-3 is a factor.

What are the steps to show a linear expression is a factor of a polynomial?

e.g. show x−2x-2 is a factor of f(x)=x5−32f(x)=x^5-32

  1. Set the linear expression to zero: x−2=0x-2=0, so x=2x=2.
  2. Substitute: f(2)=25−32=0f(2)=2^5-32=0.
  3. Since f(2)=0f(2)=0, x−2x-2 is a factor.

True or false? If f(3)=0f(3)=0 then (x+3)(x+3) is a factor of f(x)f(x).

False. f(3)=0f(3)=0 means (x−3)(x-3) is a factor.

True or false? The factor theorem can only be used with whole-number values of xx.

False. It works for rational values too, e.g. test x=23x=\frac{2}{3} to check whether 3x−23x-2 is a factor.

A cubic is written as f(x)=(x−1)(2x+1)(x−4)f(x)=(x-1)(2x+1)(x-4). What are the roots of f(x)=0f(x)=0?

x=1x=1, x=−12x=-\frac{1}{2}, x=4x=4 — set each factor equal to zero.

What are the steps to solve a cubic equation by factorising?

e.g. solve x3+x2−10x+8=0x^3+x^2-10x+8=0

  1. Find a root: f(1)=1+1−10+8=0f(1)=1+1-10+8=0, so (x−1)(x-1) is a factor.
  2. Factorise fully: (x−1)(x−2)(x+4)=0(x-1)(x-2)(x+4)=0.
  3. Set each factor to zero: x=1x=1, x=2x=2, x=−4x=-4.

What are the steps to find the remaining factors of a cubic when one factor is given?

e.g. (x+1)(x+1) is a factor of x3+2x2−x−2x^3+2x^2-x-2

  1. Divide the cubic by the given factor (or compare coefficients): x2+x−2x^2+x-2.
  2. Factorise the quadratic: (x+2)(x−1)(x+2)(x-1).
  3. Remaining factors: (x+2)(x+2) and (x−1)(x-1).

What are the steps to find an unknown coefficient when a linear expression is a factor?

e.g. (x−2)(x-2) is a factor of f(x)=x3+kx2−4x+4f(x)=x^3+kx^2-4x+4

  1. The factor gives x=2x=2, so f(2)=0f(2)=0.
  2. Substitute: 8+4k−8+4=08+4k-8+4=0.
  3. Solve: 4k+4=04k+4=0, so k=−1k=-1.

What are the steps to solve a cubic exactly when its quadratic factor does not factorise?

e.g. solve (x−2)(x2−2x−2)=0(x-2)(x^2-2x-2)=0

  1. First factor gives x=2x=2.
  2. Use the quadratic formula on x2−2x−2=0x^2-2x-2=0: x=2±122x=\frac{2\pm\sqrt{12}}{2}.
  3. Simplify the surd: x=2x=2, x=1+3x=1+\sqrt{3}, x=1−3x=1-\sqrt{3}.

What are the steps to form a cubic equation from a volume problem?

e.g. a cuboid with sides xx, x+1x+1 and x+3x+3 has volume 2424

  1. Multiply the dimensions: x(x+1)(x+3)x(x+1)(x+3).
  2. Expand: x3+4x2+3xx^3+4x^2+3x.
  3. Set equal to the given volume and rearrange: x3+4x2+3x−24=0x^3+4x^2+3x-24=0.

What are the steps to fully factorise a cubic with leading coefficient 11?

e.g. factorise x3−2x2−5x+6x^3-2x^2-5x+6

  1. Test x=x= factors of the constant term until f(x)=0f(x)=0: f(1)=0f(1)=0, so (x−1)(x-1) is a factor.
  2. Divide (or compare coefficients) to get the quadratic: x2−x−6x^2-x-6.
  3. Factorise the quadratic: (x−1)(x−3)(x+2)(x-1)(x-3)(x+2).

When hunting for a factor of a cubic whose leading coefficient is not 11, which values of xx should you test?

e.g. f(x)=2x3−x2−8x+4f(x)=2x^3-x^2-8x+4

x=pqx=\frac{p}{q}, where pp is a factor of the constant term and qq is a factor of the leading coefficient.

e.g. test ±1,±2,±4,±12\pm1,\pm2,\pm4,\pm\frac{1}{2}.