Amount of Substance & Gas Volume Flashcards

All 6 cards in this deck

What is the volume of one mole of any gas at room temperature and pressure (rtp)?

2424 dm3^3 (= 24 00024\,000 cm3^3), at 20 °C and 1 atmosphere pressure.

True or false? At rtp, 1 mole of carbon dioxide occupies a larger volume than 1 mole of hydrogen because its molecules are heavier.

False. Equal amounts in moles of any gases occupy the same volume at the same temperature and pressure — both occupy 2424 dm3^3.

What are the steps to calculate the volume of a gas at rtp from its mass?

e.g. 8 g of oxygen, Mr(O2)=32M_r(\mathrm{O_2}) = 32

  1. Moles == mass ÷Mr=8÷32=0.25\div M_r = 8 \div 32 = 0.25 mol
  2. Volume == moles ×24=0.25×24\times 24 = 0.25 \times 24
  3. =6= 6 dm3^3

What are the steps to calculate the mass of a gas from its volume at rtp?

e.g. 48 dm3^3 of oxygen, Mr(O2)=32M_r(\mathrm{O_2}) = 32

  1. Rearrange volume == moles ×24\times 24 to moles == volume ÷24=48÷24=2\div 24 = 48 \div 24 = 2 mol
  2. Mass == moles ×Mr=2×32\times M_r = 2 \times 32
  3. =64= 64 g

What are the steps to calculate the volume of a gas produced at rtp from a given mass of a solid reactant?

e.g. 10 g of CaCO3\mathrm{CaCO_3} in CaCO3→CaO+CO2\mathrm{CaCO_3 \rightarrow CaO + CO_2}, Mr(CaCO3)=100M_r(\mathrm{CaCO_3}) = 100

  1. Moles of solid == mass ÷Mr=10÷100=0.1\div M_r = 10 \div 100 = 0.1 mol
  2. Use the equation ratio: moles CO2=1:1=0.1\mathrm{CO_2} = 1 : 1 = 0.1 mol
  3. Volume =0.1×24=2.4= 0.1 \times 24 = 2.4 dm3^3

What are the steps to calculate the volume of one gas from a given volume of another gas in the same reaction?

e.g. oxygen needed for 50 cm3^3 of hydrogen in 2H2+O2→2H2O\mathrm{2H_2 + O_2 \rightarrow 2H_2O}

  1. Read the mole ratio from the equation: H2:O2=2:1\mathrm{H_2 : O_2} = 2 : 1
  2. Gas volumes are in the same ratio as the moles, so volume of O2=50÷2\mathrm{O_2} = 50 \div 2
  3. =25= 25 cm3^3 (keep both volumes in the same unit; 11 dm3=1000^3 = 1000 cm3^3)