Amounts of Substances in Equations Flashcards

All 5 cards in this deck

What do the balancing numbers in a symbol equation tell you?
e.g. 2Mg+O2→2MgO2\mathrm{Mg} + \mathrm{O_2} \rightarrow 2\mathrm{MgO}

The ratio of the amounts in moles of reactants and products.
e.g. 2 mol Mg react with 1 mol O2\mathrm{O_2} to make 2 mol MgO.

What are the steps to calculate the mass of a product from a given mass of reactant?
e.g. mass of MgO from 48 g of Mg in 2Mg+O2→2MgO2\mathrm{Mg} + \mathrm{O_2} \rightarrow 2\mathrm{MgO} (ArA_r Mg = 24, MrM_r MgO = 40)

  1. moles of reactant = 48÷2448 \div 24 = 2 mol Mg
  2. Use the equation ratio (2 : 2) = 2 mol MgO
  3. mass = moles ×Mr\times M_r = 2×402 \times 40 = 80 g

What are the steps to calculate the mass of reactant needed to make a given mass of product?
e.g. mass of CaCO3\mathrm{CaCO_3} needed to make 5.6 g of CaO in CaCO3→CaO+CO2\mathrm{CaCO_3} \rightarrow \mathrm{CaO} + \mathrm{CO_2} (MrM_r CaO = 56, CaCO3\mathrm{CaCO_3} = 100)

  1. moles of product = 5.6÷565.6 \div 56 = 0.1 mol CaO
  2. Use the equation ratio (1 : 1) = 0.1 mol CaCO3\mathrm{CaCO_3}
  3. mass = 0.1×1000.1 \times 100 = 10 g

True or false? In 2H2+O2→2H2O2\mathrm{H_2} + \mathrm{O_2} \rightarrow 2\mathrm{H_2O}, 2 g of hydrogen reacts with 1 g of oxygen.

False. The balancing numbers give the ratio in moles, not the ratio of masses in grams.

What must you do with a mass given in kilograms before using it in a moles calculation?

Convert it to grams by multiplying by 1000.
e.g. 40.0 kg = 40 000 g.